Riješi h(u)=(3u^2+5)^3(3u-1)^2 | Microsoft Math Solver

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https://socratic.org/questions/if-p-u-13u-2-29u-25-how-do-you-use-synthetic-division-to-find-p-3

https://socratic.org/questions/find-the-sum-of-1-2-5-2-9-2-81-2

https://socratic.org/questions/how-do-you-differentiate-g-u-u-2-u-3-u-5-u-2-using-the-product-rule

https://math.stackexchange.com/questions/1123189/use-induction-to-prove-that-sum-of-the-first-2n-terms-of-the-series-12-325

https://math.stackexchange.com/questions/2370334/how-to-calculate-how-many-numbers-z-of-the-form-z-p2-q3-where-p-and

https://math.stackexchange.com/questions/2883078/let-fle-to-le-u-mapsto-fu-u3-u-circ-u-circ-u-then-f-is-differen

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\left(27\left(u^{2}\right)^{3}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

Koristite binomnu teoremu \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} da biste proširili \left(3u^{2}+5\right)^{3}.

\left(27u^{6}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

Da biste podigli stepen na neki drugi stepen, pomnožite eksponente. Pomnožite 2 i 3 da biste dobili 6.

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(3u-1\right)^{2}

Da biste podigli stepen na neki drugi stepen, pomnožite eksponente. Pomnožite 2 i 2 da biste dobili 4.

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(9u^{2}-6u+1\right)

Koristite binomnu teoremu \left(a-b\right)^{2}=a^{2}-2ab+b^{2} da biste proširili \left(3u-1\right)^{2}.

243u^{8}-162u^{7}+1242u^{6}-810u^{5}+2160u^{4}-1350u^{3}+1350u^{2}-750u+125

Koristite svojstvo distributivnosti da biste pomnožili 27u^{6}+135u^{4}+225u^{2}+125 s 9u^{2}-6u+1 i kombinirali slične pojmove.

\left(27\left(u^{2}\right)^{3}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

Koristite binomnu teoremu \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} da biste proširili \left(3u^{2}+5\right)^{3}.

\left(27u^{6}+135\left(u^{2}\right)^{2}+225u^{2}+125\right)\left(3u-1\right)^{2}

Da biste podigli stepen na neki drugi stepen, pomnožite eksponente. Pomnožite 2 i 3 da biste dobili 6.

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(3u-1\right)^{2}

Da biste podigli stepen na neki drugi stepen, pomnožite eksponente. Pomnožite 2 i 2 da biste dobili 4.

\left(27u^{6}+135u^{4}+225u^{2}+125\right)\left(9u^{2}-6u+1\right)

Koristite binomnu teoremu \left(a-b\right)^{2}=a^{2}-2ab+b^{2} da biste proširili \left(3u-1\right)^{2}.

243u^{8}-162u^{7}+1242u^{6}-810u^{5}+2160u^{4}-1350u^{3}+1350u^{2}-750u+125

Koristite svojstvo distributivnosti da biste pomnožili 27u^{6}+135u^{4}+225u^{2}+125 s 9u^{2}-6u+1 i kombinirali slične pojmove.

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