Riješi 2500AB*25BC=19x+AB

$$2500 A B \times 25 B C = 19 x + A B$$

Riješite za A (complex solution)

$$\left\{\begin{matrix}A=\frac{19x}{B\left(62500BC-1\right)}\text{, }&\left(C=0\text{ or }B\neq \frac{1}{62500C}\right)\text{ and }B\neq 0\\A\in \mathrm{C}\text{, }&\left(x=0\text{ and }B=0\right)\text{ or }\left(x=0\text{ and }B=\frac{1}{62500C}\text{ and }C\neq 0\right)\end{matrix}\right,$$

Koraci za rješavanje linearne jednačine

Pomnožite B i B da biste dobili B^{2}.

$$2500AB^{2}\times 25C=19x+AB$$

Pomnožite 2500 i 25 da biste dobili 62500.

$$62500AB^{2}C=19x+AB$$

Oduzmite AB s obje strane.

$$62500AB^{2}C-AB=19x$$

Kombinirajte sve termine koji sadrže A.

$$\left(62500B^{2}C-B\right)A=19x$$

Jednačina je u standardnom obliku.

$$\left(62500CB^{2}-B\right)A=19x$$

Podijelite obje strane s 62500CB^{2}-B.

$$\frac{\left(62500CB^{2}-B\right)A}{62500CB^{2}-B}=\frac{19x}{62500CB^{2}-B}$$

Dijelјenje sa 62500CB^{2}-B poništava množenje sa 62500CB^{2}-B.

$$A=\frac{19x}{62500CB^{2}-B}$$

Podijelite 19x sa 62500CB^{2}-B.

$$A=\frac{19x}{B\left(62500BC-1\right)}$$

Riješite za A

$$\left\{\begin{matrix}A=\frac{19x}{B\left(62500BC-1\right)}\text{, }&\left(C=0\text{ or }B\neq \frac{1}{62500C}\right)\text{ and }B\neq 0\\A\in \mathrm{R}\text{, }&\left(x=0\text{ and }B=0\right)\text{ or }\left(x=0\text{ and }B=\frac{1}{62500C}\text{ and }C\neq 0\right)\end{matrix}\right,$$

Koraci za rješavanje linearne jednačine

Pomnožite B i B da biste dobili B^{2}.

$$2500AB^{2}\times 25C=19x+AB$$

Pomnožite 2500 i 25 da biste dobili 62500.

$$62500AB^{2}C=19x+AB$$

Oduzmite AB s obje strane.

$$62500AB^{2}C-AB=19x$$

Kombinirajte sve termine koji sadrže A.

$$\left(62500B^{2}C-B\right)A=19x$$

Jednačina je u standardnom obliku.

$$\left(62500CB^{2}-B\right)A=19x$$

Podijelite obje strane s 62500CB^{2}-B.

$$\frac{\left(62500CB^{2}-B\right)A}{62500CB^{2}-B}=\frac{19x}{62500CB^{2}-B}$$

Dijelјenje sa 62500CB^{2}-B poništava množenje sa 62500CB^{2}-B.

$$A=\frac{19x}{62500CB^{2}-B}$$

Podijelite 19x sa 62500CB^{2}-B.

$$A=\frac{19x}{B\left(62500BC-1\right)}$$

Riješite za B (complex solution)

$$\left\{\begin{matrix}B=\frac{\sqrt{A\left(4750000Cx+A\right)}+A}{125000AC}\text{; }B=\frac{-\sqrt{A\left(4750000Cx+A\right)}+A}{125000AC}\text{, }&C\neq 0\text{ and }A\neq 0\\B=-\frac{19x}{A}\text{, }&C=0\text{ and }A\neq 0\\B\in \mathrm{C}\text{, }&A=0\text{ and }x=0\end{matrix}\right,$$

Riješite za B

$$\left\{\begin{matrix}B=\frac{\sqrt{A\left(4750000Cx+A\right)}+A}{125000AC}\text{; }B=\frac{-\sqrt{A\left(4750000Cx+A\right)}+A}{125000AC}\text{, }&\left(C\neq 0\text{ and }x\neq 0\text{ and }A=-4750000Cx\right)\text{ or }\left(C\neq 0\text{ and }A\leq -4750000Cx\text{ and }A<0\right)\text{ or }\left(C\neq 0\text{ and }A\geq -4750000Cx\text{ and }A>0\right)\\B=-\frac{19x}{A}\text{, }&C=0\text{ and }A\neq 0\\B\in \mathrm{R}\text{, }&A=0\text{ and }x=0\end{matrix}\right,$$