Riješi (1/9alpha+1/5q)*alpha^2/28 | Microsoft Math Solver

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Slični problemi iz web pretrage

https://math.stackexchange.com/questions/1442709/convergence-of-sequence-of-the-form-a-n-frac1n-alpha-cdots-frac1

https://socratic.org/questions/how-do-you-divide-6-02-10-23-1-5-10-12

https://math.stackexchange.com/questions/1047080/prove-1-frac14-frac19-cdots-frac1n2-2-frac1n

https://math.stackexchange.com/questions/30409/generalization-of-the-series-for-frac-pi26-is-there-a-more-elementary-p

https://math.stackexchange.com/questions/1495204/on-the-binomial-series-1-frac18n1-2-where-n-is-an-even-perfect-nu

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\left(\frac{5q}{45q\alpha }+\frac{9\alpha }{45q\alpha }\right)\times \frac{\alpha ^{2}}{28}

Da biste izvršili zbrajanje ili oduzimanje izraza, rastavite ih kako bi im nazivnici bili isti. Najmanji zajednički množilac brojeva 9\alpha i 5q je 45q\alpha . Pomnožite \frac{1}{9\alpha } i \frac{5q}{5q}. Pomnožite \frac{1}{5q} i \frac{9\alpha }{9\alpha }.

\frac{5q+9\alpha }{45q\alpha }\times \frac{\alpha ^{2}}{28}

Pošto \frac{5q}{45q\alpha } i \frac{9\alpha }{45q\alpha } imaju isti imenilac, saberite ih tako što ćete sabrati njihove brojioce.

\frac{\left(5q+9\alpha \right)\alpha ^{2}}{45q\alpha \times 28}

Pomnožite \frac{5q+9\alpha }{45q\alpha } i \frac{\alpha ^{2}}{28} tako što ćete pomnožiti brojilac s brojiocem i imenilac s imeniocem.

\frac{\alpha \left(5q+9\alpha \right)}{28\times 45q}

Otkaži \alpha u brojiocu i imeniocu.

\frac{\alpha \left(5q+9\alpha \right)}{1260q}

Pomnožite 28 i 45 da biste dobili 1260.

\frac{5\alpha q+9\alpha ^{2}}{1260q}

Koristite distributivno svojstvo da biste pomnožili \alpha sa 5q+9\alpha .

\left(\frac{5q}{45q\alpha }+\frac{9\alpha }{45q\alpha }\right)\times \frac{\alpha ^{2}}{28}

\frac{5q+9\alpha }{45q\alpha }\times \frac{\alpha ^{2}}{28}