Riješi {left(3/21/4+1/510/3right)}^2+1=

$${ \left( \frac{ 3 }{ 2 } \frac{ 1 }{ 4 } + \frac{ 1 }{ 5 } \frac{ 10 }{ 3 } \right) }^{ 2 } +1=$$

Procijeni

$$\frac{1201}{576}\approx 2,085069444$$

Koraci za rješenje

Pomnožite \frac{3}{2} i \frac{1}{4} da biste dobili \frac{3}{8}.

$$\left(\frac{3}{8}+\frac{1}{5}\times \frac{10}{3}\right)^{2}+1$$

Pomnožite \frac{1}{5} i \frac{10}{3} da biste dobili \frac{2}{3}.

$$\left(\frac{3}{8}+\frac{2}{3}\right)^{2}+1$$

Saberite \frac{3}{8} i \frac{2}{3} da biste dobili \frac{25}{24}.

$$\left(\frac{25}{24}\right)^{2}+1$$

Izračunajte \frac{25}{24} stepen od 2 i dobijte \frac{625}{576}.

$$\frac{625}{576}+1$$

Saberite \frac{625}{576} i 1 da biste dobili \frac{1201}{576}.

$$\frac{1201}{576}$$

Faktor

$$\frac{1201}{2 ^ {6} \cdot 3 ^ {2}} = 2\frac{49}{576} = 2,0850694444444446$$