Riješi tan^2θ-sec^2θ=

$$\tan ^ { 2 } \theta - \sec ^ { 2 } \theta =$$

Faktor

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Koraci za rješenje

Razlika kvadrata se može faktorirati koristeći pravila: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

$$\left(\tan(\theta )-\frac{1}{\cos(\theta )}\right)\left(\tan(\theta )+\frac{1}{\cos(\theta )}\right)$$

Razmotrite \tan(\theta )-\frac{1}{\cos(\theta )}. Izbacite \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )-1}{\cos(\theta )}$$

Razmotrite \tan(\theta )+\frac{1}{\cos(\theta )}. Izbacite \frac{1}{\cos(\theta )}.

$$\frac{\sin(\theta )+1}{\cos(\theta )}$$

Ponovo napišite cijeli faktorirani izraz.

$$\left(\sin(\theta )-1\right)\left(\sin(\theta )+1\right)\times \left(\frac{1}{\cos(\theta )}\right)^{2}$$

Procijeni

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