sin(-5pidiv6)-এর সমাধান করুন

$$\sin ( -5 \pi \div 6 )$$

মূল্যায়ন করুন

$$-\frac{1}{2}=-0.5$$

সমাধানের ধাপগুলো

Use \sin(x+y)=\sin(x)\cos(y)+\sin(y)\cos(x) where x=\frac{\pi }{2} and y=\frac{\pi }{3} to obtain the result.

$$\sin(\frac{\pi }{2}+\frac{\pi }{3})=\sin(\frac{\pi }{2})\cos(\frac{\pi }{3})+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Get the value of \sin(\frac{\pi }{2}) from trigonometric values table.

$$1\cos(\frac{\pi }{3})+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Get the value of \cos(\frac{\pi }{3}) from trigonometric values table.

$$1\times \frac{1}{2}+\sin(\frac{\pi }{3})\cos(\frac{\pi }{2})$$

Get the value of \sin(\frac{\pi }{3}) from trigonometric values table.

$$1\times \frac{1}{2}+\frac{\sqrt{3}}{2}\cos(\frac{\pi }{2})$$

Get the value of \cos(\frac{\pi }{2}) from trigonometric values table.

$$1\times \frac{1}{2}+\frac{\sqrt{3}}{2}\times 0$$

গণনাটি করুন৷

$$\frac{1}{2}$$

ভাঙা

$$-\frac{1}{2} = -0.5$$