∫ (from 0 to 3) of (2x-6) wrt x-এর সমাধান করুন

$$\int _ { 0 } ^ { 3 } ( 2 x - 6 ) d x$$

মূল্যায়ন করুন

$$-9$$

সমাধানের ধাপগুলো

Evaluate the indefinite integral first.

$$\int 2x-6\mathrm{d}x$$

Integrate the sum term by term.

$$\int 2x\mathrm{d}x+\int -6\mathrm{d}x$$

Factor out the constant in each of the terms.

$$2\int x\mathrm{d}x+\int -6\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. 2 কে \frac{x^{2}}{2} বার গুণ করুন।

$$x^{2}+\int -6\mathrm{d}x$$

Find the integral of -6 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$x^{2}-6x$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$3^{2}-6\times 3-\left(0^{2}-6\times 0\right)$$

সিমপ্লিফাই।

$$-9$$