∫ (from 0 to 1) of 2-x-y wrt x-এর সমাধান করুন

$$\int _ { 0 } ^ { 1 } 2 - x - y d x$$

মূল্যায়ন করুন

$$\frac{3}{2}-y$$

সমাধানের ধাপগুলো

Evaluate the indefinite integral first.

$$\int 2-x-y\mathrm{d}x$$

Integrate the sum term by term.

$$\int 2\mathrm{d}x+\int -x\mathrm{d}x+\int -y\mathrm{d}x$$

Factor out the constant in each of the terms.

$$\int 2\mathrm{d}x-\int x\mathrm{d}x-\int y\mathrm{d}x$$

Find the integral of 2 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$2x-\int x\mathrm{d}x-\int y\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x\mathrm{d}x with \frac{x^{2}}{2}. -1 কে \frac{x^{2}}{2} বার গুণ করুন।

$$2x-\frac{x^{2}}{2}-\int y\mathrm{d}x$$

Find the integral of y using the table of common integrals rule \int a\mathrm{d}x=ax.

$$2x-\frac{x^{2}}{2}-yx$$

The definite integral is the antiderivative of the expression evaluated at the upper limit of integration minus the antiderivative evaluated at the lower limit of integration.

$$2\times 1-\frac{1^{2}}{2}-y-\left(2\times 0-\frac{0^{2}}{2}-y\times 0\right)$$

সিমপ্লিফাই।

$$\frac{3}{2}-y$$

w.r.t. y পার্থক্য করুন

$$-1$$