∫ (x^2-2sqrt{x}) wrt x-এর সমাধান করুন

$$\int ( x ^ { 2 } - 2 \sqrt { x } ) d x$$

মূল্যায়ন করুন

$$\frac{x^{3}}{3}-\frac{4x^{\frac{3}{2}}}{3}+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int x^{2}\mathrm{d}x+\int -2\sqrt{x}\mathrm{d}x$$

Factor out the constant in each of the terms.

$$\int x^{2}\mathrm{d}x-2\int \sqrt{x}\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{2}\mathrm{d}x with \frac{x^{3}}{3}.

$$\frac{x^{3}}{3}-2\int \sqrt{x}\mathrm{d}x$$

x^{\frac{1}{2}} হিসেবে \sqrt{x} পুনরায় লিখুন৷ Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{\frac{1}{2}}\mathrm{d}x with \frac{x^{\frac{3}{2}}}{\frac{3}{2}}. সিমপ্লিফাই। -2 কে \frac{2x^{\frac{3}{2}}}{3} বার গুণ করুন।

$$\frac{x^{3}-4x^{\frac{3}{2}}}{3}$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{3}}{3}-\frac{4x^{\frac{3}{2}}}{3}+С$$

w.r.t. x পার্থক্য করুন

$$x^{2}-2\sqrt{x}$$