∫ (3x^5-3x^3+1) wrt x-এর সমাধান করুন

$$\int ( 3 x ^ { 5 } - 3 x ^ { 3 } + 1 ) d x$$

মূল্যায়ন করুন

$$\frac{x^{6}}{2}-\frac{3x^{4}}{4}+x+С$$

সমাধানের ধাপগুলো

Integrate the sum term by term.

$$\int 3x^{5}\mathrm{d}x+\int -3x^{3}\mathrm{d}x+\int 1\mathrm{d}x$$

Factor out the constant in each of the terms.

$$3\int x^{5}\mathrm{d}x-3\int x^{3}\mathrm{d}x+\int 1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{5}\mathrm{d}x with \frac{x^{6}}{6}. 3 কে \frac{x^{6}}{6} বার গুণ করুন।

$$\frac{x^{6}}{2}-3\int x^{3}\mathrm{d}x+\int 1\mathrm{d}x$$

Since \int x^{k}\mathrm{d}x=\frac{x^{k+1}}{k+1} for k\neq -1, replace \int x^{3}\mathrm{d}x with \frac{x^{4}}{4}. -3 কে \frac{x^{4}}{4} বার গুণ করুন।

$$\frac{x^{6}}{2}-\frac{3x^{4}}{4}+\int 1\mathrm{d}x$$

Find the integral of 1 using the table of common integrals rule \int a\mathrm{d}x=ax.

$$\frac{x^{6}}{2}-\frac{3x^{4}}{4}+x$$

If F\left(x\right) is an antiderivative of f\left(x\right), then the set of all antiderivatives of f\left(x\right) is given by F\left(x\right)+C. Therefore, add the constant of integration C\in \mathrm{R} to the result.

$$\frac{x^{6}}{2}-\frac{3x^{4}}{4}+x+С$$

w.r.t. x পার্থক্য করুন

$$3x^{5}-3x^{3}+1$$