Решете l^alpha=pi^3+pi^4

$$l ^ { \alpha } = \pi ^ { 3 } + \pi ^ { 4 }$$

Решаване за l

$$\left\{\begin{matrix}l=-\left(\pi ^{3}\left(\pi +1\right)\right)^{\frac{1}{\alpha }}\text{, }&\alpha \neq 0\text{ and }Numerator(\alpha )\text{bmod}2=0\text{ and }Denominator(\alpha )\text{bmod}2=1\\l=\left(\pi ^{3}\left(\pi +1\right)\right)^{\frac{1}{\alpha }}\text{, }&\alpha \neq 0\end{matrix}\right,$$

Решаване за α

$$\alpha =\frac{\ln(\pi +1)+3\ln(\pi )}{\ln(l)}$$

$$l\neq 1\text{ and }l>0$$