Find Delta first and then compute results. Explanation: Yur equation is \displaystyle{2}{x}^{{2}}-{2}{x}+{1}={0} when you arrange your original equation. Now you can compute Delta: \displaystyle\Delta={b}^{{2}}-{4}{a}{c} ...

Well you will first need to factorise the function. By applying formula method, we get the roots as x = \dfrac{6 ± \sqrt(24)}{2} x = 3+\sqrt6 ; 3-\sqrt6 (x - 3 - \sqrt6) . (x - 3 + \sqrt6) < 0 ...

The discriminant of an equation tells the nature of the roots of a quadratic equation given that a,b and c are rational numbers. \displaystyle{D}={52} Explanation: The discriminant of a ...

My first reaction was that yes, there is asymmetry in the sense you are speaking of. It seems that if you denote by I increase by percentage and by D decrease by percentage, that the whole thing ...

Vertex: \displaystyle{\left(-{1},{0}\right)} Axis of symmetry: \displaystyle{x}=-{1} Explanation: \displaystyle{f{{\left({x}\right)}}}={a}{x}^{{2}}+{b}{x}+{c} Vertex: \displaystyle{\left(-\frac{{b}}{{{2}{a}}},{f{{\left(-\frac{{b}}{{{2}{a}}}\right)}}}\right)} ...

Factorise the quadratic equation Explanation: From \displaystyle{y}=-{x}^{{2}}-{2}{x}+{3} , it can be factorised to \displaystyle{y}={\left(-{x}+{1}\right)}{\left({x}+{3}\right)} From ...