Решете (beta)^2+(tanalpha-tanbeta)^2-/sec^2alphasec^2beta

$$( \beta ) ^ { 2 } + ( \tan \alpha - \tan \beta ) ^ { 2 } - \frac { } { \sec ^ { 2 } \alpha \sec ^ { 2 } \beta }$$

Изчисляване

$$\frac{-2\left(\cos(\alpha )\cos(\beta )\right)^{4}+2\left(\beta \cos(\alpha )\cos(\beta )\right)^{2}+2\left(\sin(\alpha )\cos(\beta )\right)^{2}+2\left(\sin(\beta )\cos(\alpha )\right)^{2}-\sin(2\alpha )\sin(2\beta )}{2\left(\cos(\alpha )\cos(\beta )\right)^{2}}$$

Диференциране по отношение на β

$$2\left(-\frac{\sin(\alpha -\beta )}{\cos(\alpha )\left(\cos(\beta )\right)^{3}}+\frac{1}{2}\sin(2\beta )\left(\cos(\alpha )\right)^{2}+\beta \right)$$