I _ { 1 } = ∫ (from 0 to infty) of int_0^inftye^-x^2e^-y^2 wrt xdy

I_1 üçün həll et

I_{1}=\int _{0}^{\infty}\int _{0}^{\infty}e^{-x^{2}-y^{2}}\mathrm{d}x\mathrm{d}y

I_1 təyin et

I_{1}≔\int _{0}^{\infty}\int _{0}^{\infty}e^{-x^{2}-y^{2}}\mathrm{d}x\mathrm{d}y

Sorğu

Integration

5 oxşar problemlər:

I _ { 1 } = \int _ { 0 } ^ { \infty } \int _ { 0 } ^ { \infty } e ^ { - x ^ { 2 } } e ^ { - y ^ { 2 } } d x d y

Veb Axtarışdan Oxşar Problemlər

Evaluate \int_0^{\infty}\int_0^{\infty}e^{-x^2-2xy-y^2}\,dx\,dy

https://math.stackexchange.com/questions/830755/evaluate-int-0-infty-int-0-inftye-x2-2xy-y2-dx-dy

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Evaluating the improper integral \int_0^\infty \int_0^\infty e^{-(2x+7y)}\mathop{\mathrm dy} \mathop{\mathrm dx}

https://math.stackexchange.com/questions/2016227/evaluating-the-improper-integral-int-0-infty-int-0-infty-e-2x7y-matho

Hint: this problem actually reduces to calculating \left(\int_0^{\infty}e^{-2x}\,dx\right)\cdot\left(\int_0^{\infty}e^{-7y}\,dy\right) Why?

How to calculate \iint_{\mathbb{R}^2} \exp\left(-x^2-y^2+ixy-ix-iy\right)\,dx\,dy?

https://math.stackexchange.com/questions/2622068/how-to-calculate-iint-mathbbr2-exp-left-x2-y2ixy-ix-iy-right-dx

This is a Gaussian double-integral I ~:=~\iint_{\mathbb{R}^2} \! dx~dy~ e^{-S(x,y)} ,\tag{1} where S(x,y)~:=~x^2+y^2-ixy+ix+iy. \tag{2} One method is to change coordinates x^{\pm}=\frac{x\pm y}{\sqrt{2}} ...

Obtaining a joint density function from a given function by scaling

https://math.stackexchange.com/q/2662355

Observe that we can factor the joint density as f(x,y)=e^{-\lambda x}e^{-\lambda y}; \quad (x,y\geq 0)\tag{1}. Let I=\int_0^\infty\int_0^\infty f(x,y)\,dx\,dy and note that I=\int_0^\infty\int_0^\infty e^{-\lambda x}e^{-\lambda y}\, dx \,dy =\int_0^\infty e^{-\lambda y}\left[\int_0^\infty e^{-\lambda x}\, dx \right]\,dy =\left[\int_0^\infty e^{-\lambda x}\, dx \right]\left[\int_0^\infty e^{-\lambda y}\, dy \right] ...

Need help understanding why \int_0^\infty \int_0^\infty |x-y|e^{-x}e^{-y} \, dx \,dy = 2 \int_0^\infty \int_y^\infty (x-y)e^{-x}e^{-y} \, dx \,dy

https://math.stackexchange.com/questions/3081376/need-help-understanding-why-int-0-infty-int-0-infty-x-ye-xe-y-dx

Note that \tag{*} \int_0^\infty\int_0^\infty |x-y|e^{-x}e^{-y} \, dx\, dy \\ = \int_0^\infty\int_y^\infty (x-y)e^{-x}e^{-y} \, dx\, dy + \int_0^\infty\int_0^y (y-x)e^{-x}e^{-y} \, dx\, dy The ...

Integral of exponent \iint\limits_0^\infty e^{(t_1 x+t_2 y -y) }\ dy\ dx

https://math.stackexchange.com/questions/968120/integral-of-exponent-iint-limits-0-infty-et-1-xt-2-y-y-dy-dx

Let's integrate with respect to x first. \int\limits_0^\infty \int\limits_0^\infty e^{(t_1x+t_2y-y) }\ dy\ dx = \int\limits_0^\infty \left( \int\limits_0^\infty e^{(t_1x+t_2y-y) }\ dx\right)dy \\ = \int\limits_0^\infty \left(\lim_{N \to \infty} \frac{1}{t_1}\left[e^{(t_1x+t_2y-y) } \right]\Big|_0^N \right)dy ...

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{ x } ^ { 2 } - 4 x - 5 = 0

Triqonometriya

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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Eyni vaxtda tənlik

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

İnteqrasiya

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Limitlər

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