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Amil

\frac{e^{2}AWorw之吗将微星有真金麻乐^{2}作^{2}俱^{2}助^{2}州^{2}弊^{2}辅^{2}部^{2}P^{3}k^{3}p^{3}克^{3}器^{3}视^{3}透^{3}\left(\frac{iaf_{15}n维}{d}+了解\right)外^{4}扑^{4}挂^{5}\tan(iabosxl^{2})}{德^{3}}

Sorğu

Complex Number

5 oxşar problemlər:

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Applying row operations to a matrix in order to get a diagonal matrix

https://math.stackexchange.com/questions/286094/applying-row-operations-to-a-matrix-in-order-to-get-a-diagonal-matrix

You can't always, e.g. there's no way to get a diagonal matrix from \pmatrix{1 & 1\cr 0 & 0\cr} by these operations. But if you don't run into any inconvenient zeros, it is possible. First add ...

Is that a metric?

https://math.stackexchange.com/questions/2113088/is-that-a-metric

Ok, I got the answer to the more complicated claim of the authors. Let \alpha_{i,j} = \sup\{r>0: \exists \varphi:B_{G_i}(o_i,[r]) \to B_{G_j}(o_j,[r]) \text{ graph isomorphism with } \varphi(o_i)=o_j \text{ and } \|M_j \circ \varphi - M_i\|_{B_{G_i}(o_i,[r])}<1/r\} ...

Null Space versus Basis of a Null Space

https://math.stackexchange.com/questions/1166499/null-space-versus-basis-of-a-null-space

It would be correct to say that it is a basis of the null space, but not that it is (as your notation hints) the basis (i.e. the only one) of the null space.

Vector value after normalization

https://math.stackexchange.com/q/1460966

A normalized vector has unit norm, that's the definition of being normalized, and it also follows from your definition. Let's check (in symbols): \def\abs#1{\left|#1\right|}\abs{\def\n{\mathord{\rm normalized}}\n(a)} = \sqrt{\n(a).x^2 + \n(a).y^2} = \sqrt{\frac{a.x^2}{\abs a^2} + \frac{a.y^2}{\abs a^2}} = \sqrt{\frac{a.x^2 + a.y^2}{\abs a^2}} = 1 ...

Matrix raised to a power

https://math.stackexchange.com/questions/984862/matrix-raised-to-a-power

You are almost done. It remains to find the limit \lim_{n\to\infty}A^n, which is A^n= \begin{pmatrix} -1/3 & 2/3 \\ 1/3 & 1/3 \end{pmatrix}\begin{pmatrix} (2/5)^n & 0 \\ 0 & 1 \end{pmatrix}\begin{pmatrix} -1 & 2 \\ 1 & 1 \end{pmatrix}\to \begin{pmatrix} -1/3 & 2/3 \\ 1/3 & 1/3 \end{pmatrix}\begin{pmatrix} 0 & 0 \\ 0 & 1 \end{pmatrix}\begin{pmatrix} -1 & 2 \\ 1 & 1 \end{pmatrix}= \begin{pmatrix} 2/3 & 2/3 \\ 1/3 & 1/3 \end{pmatrix}.

Gauss transforms to factor A = LU

https://math.stackexchange.com/q/1795358

You do not need the details of the construction, merely the fact that it exists. Let us write A = LU = LD\tilde{U}, where L is unit lower-triangular as assumed, and where \tilde{U} is unit ...

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Panoya köçürüldü

Nümunələr

Quadratik tənlik

{ x } ^ { 2 } - 4 x - 5 = 0

Triqonometriya

4 \sin \theta \cos \theta = 2 \sin \theta

\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]

Eyni vaxtda tənlik

\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.

Diferensiallaşdırma

\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }

İnteqrasiya

\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x

Limitlər

\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}

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