psi^v+2^psi=0

$$\psi ^ { v } + 2 ^ { \psi } = 0$$

v üçün həll et (complex solution)

$$v=\frac{\ln(2)\psi +\pi i}{\ln(\psi )}+\frac{2\pi n_{1}i}{\ln(\psi )}$$

$$n_{1}\in \mathrm{Z}$$

$$\psi \neq 1\text{ and }\psi \neq 0$$

v üçün həll et

$$v=\psi \log_{-\psi }\left(2\right)$$

$$\psi \neq -1\text{ and }\psi <0\text{ and }Numerator(\psi \log_{-\psi }\left(2\right))\text{bmod}2=1\text{ and }Denominator(\psi \log_{-\psi }\left(2\right))\text{bmod}2=1$$