মুখ্য সমললৈ এৰি যাওক
মূল্যায়ন
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বিস্তাৰ
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ৱেব অনুসন্ধানৰ পৰা একেধৰণৰ সমস্যাসমূহ

ভাগ-বতৰা কৰক

\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(r+\frac{1}{4}s\right)^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
বৰ্গ \frac{1}{4}r-s+\frac{2}{3}t৷
\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(r^{2}+\frac{1}{2}rs+\frac{1}{16}s^{2}\right)-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\left(r+\frac{1}{4}s\right)^{2} বিস্তাৰ কৰিবলৈ দ্বিপদীয় উপপাদ্য \left(a+b\right)^{2}=a^{2}+2ab+b^{2} ব্যৱহাৰ কৰক৷
\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-r^{2}-\frac{1}{2}rs-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
r^{2}+\frac{1}{2}rs+\frac{1}{16}s^{2}ৰ বিপৰীত বিচাৰিবলৈ, প্ৰত্যেকটো পদৰ বিপৰীত অৰ্থ বিচাৰক৷
-\frac{15}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\frac{1}{2}rs-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-\frac{15}{16}r^{2} লাভ কৰিবলৈ \frac{1}{16}r^{2} আৰু -r^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-rs লাভ কৰিবলৈ -\frac{1}{2}rs আৰু -\frac{1}{2}rs একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\frac{15}{16}s^{2} লাভ কৰিবলৈ s^{2} আৰু -\frac{1}{16}s^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}\right)+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\left(s-\frac{2}{3}t\right)^{2} বিস্তাৰ কৰিবলৈ দ্বিপদীয় উপপাদ্য \left(a-b\right)^{2}=a^{2}-2ab+b^{2} ব্যৱহাৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-s^{2}+\frac{4}{3}st-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}ৰ বিপৰীত বিচাৰিবলৈ, প্ৰত্যেকটো পদৰ বিপৰীত অৰ্থ বিচাৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}+\frac{4}{3}st-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-\frac{1}{16}s^{2} লাভ কৰিবলৈ \frac{15}{16}s^{2} আৰু -s^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{4}{9}t^{2}-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
0 লাভ কৰিবলৈ -\frac{4}{3}st আৰু \frac{4}{3}st একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
0 লাভ কৰিবলৈ \frac{4}{9}t^{2} আৰু -\frac{4}{9}t^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\left(\frac{1}{16}r+\frac{1}{16}s\right)\left(15r+s\right)
\frac{1}{16}ক r+sৰে পূৰণ কৰিবলৈ বিতৰক উপাদান ব্যৱহাৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{15}{16}r^{2}+rs+\frac{1}{16}s^{2}
15r+sৰ দ্বাৰা \frac{1}{16}r+\frac{1}{16}s পূৰণ কৰিবলৈ বিভাজক সম্পত্তি ব্যৱহাৰ কৰক আৰু পদসমূহৰ দৰে একত্ৰিত কৰক৷
-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+rs+\frac{1}{16}s^{2}
0 লাভ কৰিবলৈ -\frac{15}{16}r^{2} আৰু \frac{15}{16}r^{2} একত্ৰ কৰক৷
\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{1}{16}s^{2}
0 লাভ কৰিবলৈ -rs আৰু rs একত্ৰ কৰক৷
\frac{1}{3}rt
0 লাভ কৰিবলৈ -\frac{1}{16}s^{2} আৰু \frac{1}{16}s^{2} একত্ৰ কৰক৷
\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(r+\frac{1}{4}s\right)^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
বৰ্গ \frac{1}{4}r-s+\frac{2}{3}t৷
\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(r^{2}+\frac{1}{2}rs+\frac{1}{16}s^{2}\right)-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\left(r+\frac{1}{4}s\right)^{2} বিস্তাৰ কৰিবলৈ দ্বিপদীয় উপপাদ্য \left(a+b\right)^{2}=a^{2}+2ab+b^{2} ব্যৱহাৰ কৰক৷
\frac{1}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-r^{2}-\frac{1}{2}rs-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
r^{2}+\frac{1}{2}rs+\frac{1}{16}s^{2}ৰ বিপৰীত বিচাৰিবলৈ, প্ৰত্যেকটো পদৰ বিপৰীত অৰ্থ বিচাৰক৷
-\frac{15}{16}r^{2}-\frac{1}{2}rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\frac{1}{2}rs-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-\frac{15}{16}r^{2} লাভ কৰিবলৈ \frac{1}{16}r^{2} আৰু -r^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\frac{1}{16}s^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-rs লাভ কৰিবলৈ -\frac{1}{2}rs আৰু -\frac{1}{2}rs একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(s-\frac{2}{3}t\right)^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\frac{15}{16}s^{2} লাভ কৰিবলৈ s^{2} আৰু -\frac{1}{16}s^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-\left(s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}\right)+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
\left(s-\frac{2}{3}t\right)^{2} বিস্তাৰ কৰিবলৈ দ্বিপদীয় উপপাদ্য \left(a-b\right)^{2}=a^{2}-2ab+b^{2} ব্যৱহাৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt+\frac{15}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}-s^{2}+\frac{4}{3}st-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}ৰ বিপৰীত বিচাৰিবলৈ, প্ৰত্যেকটো পদৰ বিপৰীত অৰ্থ বিচাৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}-\frac{4}{3}st+\frac{4}{9}t^{2}+\frac{4}{3}st-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
-\frac{1}{16}s^{2} লাভ কৰিবলৈ \frac{15}{16}s^{2} আৰু -s^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{4}{9}t^{2}-\frac{4}{9}t^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
0 লাভ কৰিবলৈ -\frac{4}{3}st আৰু \frac{4}{3}st একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{1}{16}\left(r+s\right)\left(15r+s\right)
0 লাভ কৰিবলৈ \frac{4}{9}t^{2} আৰু -\frac{4}{9}t^{2} একত্ৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\left(\frac{1}{16}r+\frac{1}{16}s\right)\left(15r+s\right)
\frac{1}{16}ক r+sৰে পূৰণ কৰিবলৈ বিতৰক উপাদান ব্যৱহাৰ কৰক৷
-\frac{15}{16}r^{2}-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{15}{16}r^{2}+rs+\frac{1}{16}s^{2}
15r+sৰ দ্বাৰা \frac{1}{16}r+\frac{1}{16}s পূৰণ কৰিবলৈ বিভাজক সম্পত্তি ব্যৱহাৰ কৰক আৰু পদসমূহৰ দৰে একত্ৰিত কৰক৷
-rs+\frac{1}{3}rt-\frac{1}{16}s^{2}+rs+\frac{1}{16}s^{2}
0 লাভ কৰিবলৈ -\frac{15}{16}r^{2} আৰু \frac{15}{16}r^{2} একত্ৰ কৰক৷
\frac{1}{3}rt-\frac{1}{16}s^{2}+\frac{1}{16}s^{2}
0 লাভ কৰিবলৈ -rs আৰু rs একত্ৰ কৰক৷
\frac{1}{3}rt
0 লাভ কৰিবলৈ -\frac{1}{16}s^{2} আৰু \frac{1}{16}s^{2} একত্ৰ কৰক৷