{l}{1/10U_{1}+(U_{1}-U_{2})1/2=5I_{x}+2}{1/2(U_{1}-U_{2})+5I_{x}+1/4U_{2}=0}{I_{x}=frac{6}{13}} সমাধান কৰক

$$\left. \begin{array} { l } { \frac { 1 } { 10 } U _ { 1 } + ( U _ { 1 } - U _ { 2 } ) \frac { 1 } { 2 } = 5 I _ { x } + 2 } \\ { \frac { 1 } { 2 } ( U _ { 1 } - U _ { 2 } ) + 5 I _ { x } + \frac { 1 } { 4 } U _ { 2 } = 0 } \\ { I _ { x } = \frac { 6 } { 13 } } \end{array} \right.$$

U_1, U_2, I_x-ৰ বাবে সমাধান কৰক

$$U_{1} = -\frac{290}{13} = -22\frac{4}{13} \approx -22.307692308$$

$$U_{2} = -\frac{460}{13} = -35\frac{5}{13} \approx -35.384615385$$

$$I_{x}=\frac{6}{13}\approx 0.461538462$$

অনুকল্পন ব্যৱহাৰ কৰি পৰ্যায়বোৰ সজাওক

সমীকৰণবোৰ পুনৰ ক্ৰম কৰক৷

$$I_{x}=\frac{6}{13} \frac{1}{2}\left(U_{1}-U_{2}\right)+5I_{x}+\frac{1}{4}U_{2}=0 \frac{1}{10}U_{1}+\left(U_{1}-U_{2}\right)\times \frac{1}{2}=5I_{x}+2$$

দ্বিতীয় আৰু তৃতীয় সমীকৰণত I_{x}ৰ বাবে বিকল্প \frac{6}{13}৷

$$\frac{1}{2}\left(U_{1}-U_{2}\right)+5\times \frac{6}{13}+\frac{1}{4}U_{2}=0 \frac{1}{10}U_{1}+\left(U_{1}-U_{2}\right)\times \frac{1}{2}=5\times \frac{6}{13}+2$$

U_{2} আৰু U_{1}ৰ বাবে এই সমীকৰণবোৰ সমাধান কৰক৷

$$U_{2}=\frac{120}{13}+2U_{1} U_{1}=\frac{280}{39}+\frac{5}{6}U_{2}$$

সমীকৰণ U_{1}=\frac{280}{39}+\frac{5}{6}U_{2}ত U_{2}ৰ বাবে বিকল্প \frac{120}{13}+2U_{1}৷

$$U_{1}=\frac{280}{39}+\frac{5}{6}\left(\frac{120}{13}+2U_{1}\right)$$

U_{1}ৰ বাবে U_{1}=\frac{280}{39}+\frac{5}{6}\left(\frac{120}{13}+2U_{1}\right) সমাধান কৰক৷

$$U_{1}=-\frac{290}{13}$$

সমীকৰণ U_{2}=\frac{120}{13}+2U_{1}ত U_{1}ৰ বাবে বিকল্প -\frac{290}{13}৷

$$U_{2}=\frac{120}{13}+2\left(-\frac{290}{13}\right)$$

U_{2}=\frac{120}{13}+2\left(-\frac{290}{13}\right)ৰ পৰা U_{2} গণনা কৰক৷

$$U_{2}=-\frac{460}{13}$$

ছিষ্টেমটো এতিয়া ঠিক হৈছে৷

$$U_{1}=-\frac{290}{13} U_{2}=-\frac{460}{13} I_{x}=\frac{6}{13}$$